int(cos2 theta-cos2 alpha)/(sin alpha-sin theta)d theta

Evaluate int (cos 2 theta - cos 2 alpha )/(sin alpha - sin theta ) d theta

Evaluate: int cos2 theta ln((cos theta+sin theta)/(cos theta-sin theta))d theta

int(2sin2 theta-cos theta)/(6-cos^(2)theta-4sin theta)d theta

If tan theta=(cos alpha-sin alpha)/(cos alpha+sin alpha) and theta is acute then theta+alpha=

Prove that cos 4theta–cos 4alpha = 8(cos theta-cos alpha)(cos theta+ cos alpha )(cos theta -sin alpha)(cos theta+sin alpha)

int cos 2theta log ((cos theta+sin theta)/(cos theta-sin theta))d theta

Prove that : 2 sin^2 theta + 4 cos (theta + alpha) sin alpha sin theta + cos 2 (alpha + theta) is independent of theta.

int cos2 theta * ln ((cos theta + sin theta) / (cos theta-sin theta)) d theta

If tan theta=(sin alpha-cos alpha)/(sin alpha+cos alpha) ,then theta is

If tan theta=(sin alpha- cos alpha)/(sin alpha+cos alpha) , then