If A is a square matrix, then `adj(A')-(adjA)'=`

If a is a square matrix, then adjA^(T)-(adjA)^(T)=

If A is a non-singular matrix, then A (adj.A)=

If A is square matrix of order 3 then |adj(adjA)|=(1)|A|(2)|A|^(2)(3)|A|^(3)(4)|A|^(4)

If A is square matrix of order n then adj(adjA=(1)|A|^(n-1)A(2)|A|^(n-2)A(3)|A|^(n-2)(4)|A|^(n)A

If A is a square matrix of order 2, then adj (adj A)

If A is square matrix,then prove that A.(adj*A)=absAI.

If A is a non singular square matrix,then adj(adjA)=|A|^(n-2)A

If A is a square matrix such that A(adjA)=[(4,0,0),(0,4,0),(0,0,4)], then =(|adj(adjA)|)/(2|adjA|) is equal to

If A is a square matrix such that A(adjA)=[(4,0,0),(0,4,0),(0,0,4)], then =(|adj(adjA)|)/(2|adjA|) is equal to