[x+y+z=1],[2x+2y+3z=6],[x+4y+9z=3]

x+y+z=1,2x+2y+3z=6,z+4y+9z=3 , by Gauss-Jordan method.

x+y+z=12x+2y+3z=6x+4y+9z=3 Solve the folilowing equations by Gauss - Jordan method x+y+z=12x+2y+3z=6x+4y+9z=3

The following system of linear equations has x+ 2y + 3z=1,2x + y + 3z = 2, 5x+ 5y + 9z = 4

For the equations x+2y+3z=1, 2x+y+3z=2, 5x+5y+9z=4

Solve the following system of homogeneous equations: x+y-2z=0 ,2x+y-3z=0 ,5x+4y-9z=0

3x+4y+7z=4, 2x+y+ 3z= 3, x + 2y +3z =8.

The system of equations x+y+z=6, x+2y+3z=14, x+4y=7z=30 has