[int3^(-log_(9)x^(2))dx=],[" 1) "2log|x|+cquad " 2) "log|x|+c],[" 3) "-log|x|+cquad " 4) "-2log|x|+c]

int log_(c)(1+x^(2))dx

int1/(x"log"x^(2))dx is equal to a) 1/(2)"log"|"log"x^(2)|+C b) "log"|"log"x^(2)|+C c) 2"log"|"log"x^(2)|+C d) 4"log"|"log"x^(2)|+C

int((x+1)^(2))/(x(x^(2)+1))dx is equal to a) "log"|x(x^(2)+1)|+C b) "log"|x|+C c) "log"|x|+2"tan"^(-1)x+C d) "log"(1/(1+x^(2)))+C

int(log|x|)/(x sqrt(1+log|x|))dx=...+c .

int(log(3x))/(x log(9x))dx= (a) log(3x)-log(9x)+c (b) log(x)-(log3)*log(log9x)+c (c) log9-(log x)*log(log3x)+c (d) log(x)+(log3)*log(log(9x))+c

If int (3x+4)/(x^(3)-2x-4) dx = log |x-2|+ lamda log [f(x)]+c, then-

int_(log(1/2))^(log2) log(x+sqrt(x^2+1))dx= (A) 2log2 (B) 1-log2 (C) 1+log2 (D) 0

int (log x)/(x^(2))dx is equal to a) (log x)/(x) + (1)/(x^(2)) +C b) -(log x)/(x) + (2)/(x) + C c) -(log x)/(x) - (1)/(2x) + C d) -(log x)/(x) - (1)/(x) + C

int frac{x+1}{x^2 + 5x + 6} dx=............ A) log(x+2) +2 log(x+3) + c B) log(x+2) - 2 log(x+3) + c C) -log(x+2) - 2 log(x+3) + c D) -log(x+2) + 2 log(x+3) + c