lim(xrarrpi/2)(cosx)/(pi/2-x)=...

`lim_(xrarrpi/2)(cosx)/(pi/2-x)=`

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The correct Answer is:

lim(xrarr0)sinx/sqrtx=
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lim(xrarr0)(sin3x)/sinx=
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lim(xrarrpi/2)(cosx)/(pi/2-x)=
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lim(xrarrpi/4)(sinx-cosx)/(x-pi/4)=
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lim(xrarr4)(x^(5/2)-4^(5/2))/(x-4)=
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মনে করো, f(x)=sqrt(x+3)/(x+1) , তাহলে lim(xrarr-3+0)f(x) -এর মান—
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lim(xrarr1)(x+x^2+x^3+* * *+x^n-n)/(x-1)
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lim(xrarr3)(alphax^2-beta)/(x-3)=12
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lim(xrarr-1/2)(2x^2-3x+1)/(2x-1)
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lim(xrarr1)[cos"pi/2sqrt(x^2-2x+2)]=
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lim(hrarr3)root(3)(2h^2-3h-1)=
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lim(hrarr1)(2h^2-2h+9)^(3/2)=
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lim(xrarr1)(x-1)/(sqrtx-1)=
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lim(xrarr4)(sqrtx-2)/(x-4)=
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lim(xrarr2)(x^5-32)/(x-2)=
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lim(xrarr3)(x^3-27)/(x^2-9)=
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lim(hrarr0)(3h^2-2h)/h=
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lim(xrarr16)(x^(1/4)-(16)^(1/4))/(x-16)=
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একটি অপেক্ষকের সীমার সংজ্ঞা দাও ।
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lim(xrarra)(x^n-a^n)/(x-a)=na^(n-1) সীমা সূত্রের সাহায্যে দেখাও যে , l...
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