lim(xrarr1)[cos"pi/2sqrt(x^2-2x+2)]=...

`lim_(xrarr1)[cos"pi/2sqrt(x^2-2x+2)]=`

`-1`

`1/2`

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The correct Answer is:

lim(xrarr3)(alphax^2-beta)/(x-3)=12
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lim(xrarr-1/2)(2x^2-3x+1)/(2x-1)
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lim(xrarr1)[cos"pi/2sqrt(x^2-2x+2)]=
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lim(hrarr3)root(3)(2h^2-3h-1)=
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lim(hrarr1)(2h^2-2h+9)^(3/2)=
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lim(xrarr1)(x-1)/(sqrtx-1)=
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lim(xrarr4)(sqrtx-2)/(x-4)=
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lim(xrarr2)(x^5-32)/(x-2)=
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lim(xrarr3)(x^3-27)/(x^2-9)=
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lim(hrarr0)(3h^2-2h)/h=
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lim(xrarr16)(x^(1/4)-(16)^(1/4))/(x-16)=
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একটি অপেক্ষকের সীমার সংজ্ঞা দাও ।
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lim(xrarra)(x^n-a^n)/(x-a)=na^(n-1) সীমা সূত্রের সাহায্যে দেখাও যে , l...
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lim(xrarr oo)((x+2)/(x+1))^(x+3)
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lim(xrarr1)(x^2-x)/(2(x-1))
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lim(xrarr 0)(x2^x-x)
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দেখাও যে ,lim(xrarroo)(2x+1)/x=2
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দেখাও যে ,lim(xrarr0)(x/sinx)=1
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দেখাও যে ,lim(xrarr3)(x^2-9)/(x-3)=6
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f(x)=sqrt(x-3) হলে , lim(xrarr3)f(x) - এর অস্তিত্ব আছে কি ? যুক্তিসহ ...
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