[f:[1,+oo)rarr[2,+oo)" is given by "],[(x+sqrt(x^(2)-4))/(2)],[(x)/(1+x^(2))],[(x-sqrt(x^(2)-4))/(2)],[1+sqrt(x^(2)-4)]

If F:[1,oo)vec 2,oo is given by f(x)=x+(1)/(x), then f^(-1)(x) equals.(x+sqrt(x^(2)-4))/(2)(b)(x)/(1+x^(2))(c)(x-sqrt(x^(2)-4))/(2)(d)1+sqrt(x^(2)-4)

If F:[1,x)rarr[2,x] is given by f(x)=x+(1)/(x), then f^(-1)(x) equals.(a) (x+sqrt(x^(2)-4))/(2)(b)(x)/(1+x^(2))(c)(x-sqrt(x^(2)-4))/(2) (d) 1+sqrt(x^(2)-4)

If F :[1,oo)vec[2,oo) is given by f(x)=x+1/x ,t h e nf^(-1)(x) equals. (x+sqrt(x^2-4))/2 (b) x/(1+x^2) (c) (x-sqrt(x^2-4))/2 1+sqrt(x^2-4)

If f: [1,oo) rarr [2, oo) is given by f(x) = x+1/x , then f^(-1) (x) equals a) ((x+sqrt(x^2-4)))/(2) b) x/(1+x^2) c) ((x-sqrt(x^2-4)))/(2) d) 1+sqrt(x^2-4)

if f:[1,oo)->[2,oo) is given by f(x)=x+1/x then f^-1(x) equals to : a) (x+sqrt(x^2-4))/2 b) x/(1+x^2) c) (x-sqrt(x^2-4))/2 d) 1+sqrt(x^2-4)

if f:[1,oo)->[2,oo) is given by f(x)=x+1/x then f^-1(x) equals to : a) (x+sqrt(x^2-4))/2 b) x/(1+x^2) c) (x-sqrt(x^2-4))/2 d) 1+sqrt(x^2-4)

if f:[1,oo)->[2,oo) is given by f(x)=x+1/x then f^-1(x) equals to : a) (x+sqrt(x^2-4))/2 b) x/(1+x^2) c) (x-sqrt(x^2-4))/2 d) 1+sqrt(x^2-4)

If F :[1,oo)vec[2,oo) is given by f(x)=x+1/x ,t h e nf^(-1)(x) equals. (x+sqrt(x^2-4))/2 (b) x/(1+x^2) (c) (x-sqrt(x^2-4))/2 (d) 1+sqrt(x^2-4)

Lt_(x to oo) {sqrt(x^(2)-sqrt(x^(4)+1))-x sqrt(2)}=

If F :[1,oo)->[2,oo) is given by f(x)=x+1/x ,t h e n \ f^(-1)(x) equals \ \ (a) (x+sqrt(x^2-4))/2 (b) x/(1+x^2) (c) (x-sqrt(x^2-4))/2 (d) 1+sqrt(x^2-4)