" Q8) समीकरण "x^(2)+7x+10=0" को हल "

6x^(2)+7x-10=0

Roots of x^(2)+7x+10=0 are

If P = {x | x^2 - 10x + 16 = 0} , Q = {x | x^2 - 7x + 10 = 0} R = {x | x^2 + 6x - 16 = 0} and x is universal set where x = {-2, -1, 0, 1, 2, 5, 8} then find P uu Q

If P = {x | x^2 - 10x + 16 = 0} , Q = {x | x^2 - 7x + 10 = 0} , R = {x | x^2 + 6x - 16 = 0} and x is universal set where x = {-2, -1, 0, 1, 2, 5, 8} then find Q nn R

If P = {x | x^2 - 10x + 16 = 0} , Q = {x | x^2 - 7x + 10 = 0} , R = {x | x^2 + 6x - 16 = 0} and x is universal set where x = {-2, -1, 0, 1, 2, 5, 8} then find (Q' nn R')

If P = {x | x^2 - 10x + 16 = 0} , Q = {x | x^2 - 7x + 10 = 0} , R = {x | x^2 + 6x - 16 = 0} and x is universal set where x = {-2, -1, 0, 1, 2, 5, 8} then find (P uu R)'

If P = {x | x^2 - 10x + 16 = 0} , Q = {x | x^2 - 7x + 10 = 0} , R = {x | x^2 + 6x - 16 = 0} and x is universal set where x = {-2, -1, 0, 1, 2, 5, 8} then find P uu (Q nn R)

If P = {x |x^2 - 10x + 16 = 0} , Q = {x | x^2 - 7x + 10 = 0} , R = {x | x^2 + 6x - 16 = 0} and x is universal set where x = {-2, -1, 0, 1, 2, 5, 8} then find P nn (Q uu R)

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