Determine the poisson's ratio of the material of a wire whose volume remains constant under an external normal stress.

A uniform wire of length 8m and diameter 0.6mm stretched by 4mm under a certain force. If the Poisson's ratio of the material of the wrie is 0.3, calculate the change in diameter of the wire.

A uniform wire of length 10 m and diameter 0.6 mm is stretched by 6 mm with certain force. If the Poisson's ratio of the material of the wire is 0.3, then the change in diameter of the wire is

A wire is stretched by 1% but volume remains constant, then -

A wire of length L and radius r is loaded with a weigth Mg. If y and sigma denote the Youngs modulus and Poisson's ratio of the material of the wire respectively. Then the decreases in the radius of the wire is given by

The Poisson's ratio of the material of a wire is 0.25. If it is stretched by a force F, the longitudinal strain produced in the wire is 5xx10^(-4) . What is the percentage increase in its volume?

When a load of 10 kg is suspended from one end of a wire of length 1m, it increases in length by 0.1 cm. IF the Poisson's ratio for the material of the wire is 1/3 , then calculate the change in volume of the wire, cross-sectional area of the wire =0.1 cm^2 .

The poisson ratio for the material of a wire is 0.4. When a force is applied on the wire, longitudinal strain is (1/100) . The perecentage change in the radius of the wire is