In an equilateral triangle show that the in-radius and the circum-radius are connected by r =R/2.

In an equilateral triangle r:R:r1 is

In an equilateral triangle the inradius and the circum-radius is connected by (1)r=4R(2)r=(R)/(2)(3)r=(R)/(3)(4)r=(r)/(sqrt(3))

In an equilateral triangle, inradius r , circumradius R and ex-radius r_1 are in A.P. (b) G.P. (c) H.P. (d) none of these

If the area of the triangle ABC is a^(2)-(b-c)^(2), then its circumradius R=

If the area of the triangle ABC is a^(2)-(b-c)^(2) then its circumradius R is

In a Delta ABC, 2s= perimeter and R = circumradius. Then, find s/R.

In the given figure,ABC is an equilateral triangle which is inscribed inside a circle and whose radius is r .Which of the following is the area of the triangle? (r+DE)^((1)/(2))(r-DE)^((3)/(2))(b)(r-DE)^((1)/(2))(r+DE)^(2)(c)(r-DE)^((1)/(2))(r+DE)^(2)(d)(r-DE)^((1)/(2))(r+DE)^((3)/(2))(d)

In a triangle ABC, let angleC= pi//2 . If r is the inradius and R is the circumradius of the triangle, then 2 (r + R) is equal to