If `f(x) `is continuous at `x=7`, where `f(x)=(log x-log 7)/(x-7)`, for `x!=7`, then `f(7)=`

If f(x) is continuous at x=0 , where f(x)=(log(2+x)-log(2-x))/(tan x) , for x!=0 , then f(0)=

If f(x) is continuous at x=0 , where f(x)=(log 100 + log (0.01 +x))/(3x) , for x!=0 , then f(0)=

Discuss the continuity of the functions at the points given against them. If a function is discontinuous, determine whether the discontiunity is removable. In this case, redefine the function, so that it becomes continuous : {:(f(x)=(logx-log7)/(x-7)",","for" x ne7),(=7",","for" x=7):}}at x=7.

Let f(x) be a continuous function such that f(0) = 1 and f(x)=f(x/7)=x/7 AA x in R, then f(42) is

Let f(x) be a continuous function such that f(0) = 1 and f(x)-f (x/7) = x/7 AA x in R , then f(42) is

3(log_(7)x+log_(x)7)=10

Let f(x) be a continuous function such that f(0)=1 and f(x)=f((x)/(7))=(x)/(7)AA x in R then f(42) is

Solve : 7^(log x)=98-x^(log 7)

Solve : 7^(log x)=98-x^(log 7)

If f(x) is continuous and differentiable in x in [-7,0] and f(x) le 2 AA x in [-7,0] , also f(-7)=-3 then range of f(-1)+f(0)