x=cos theta-cos20,y=sin theta-sin2 theta

If x=cos theta-cos2 theta,y=sin theta-sin2 theta then (dy)/(dx) is

x = cos theta - cos 2 theta, y = sin theta - sin 2 theta . then find dy/dx

If x=2cos theta -cos 2theta ,y=2sin theta -sin 2theta ,then (dy)/(dx) =

Find dy/dx when x = cos theta + cos 2 theta, y = sin theta + sin 2 theta)

Find (dy)/(dx) if x= 3 cos theta - cos 2theta and y= sin theta - sin 2theta.

Find (dy)/(dx) if x= 3 cos theta - cos 2theta and y= sin theta - sin 2theta.

If x=cos theta-cos 2theta and y=sin theta-sin2theta , then find (dy)/(dx) .

(sin^(2) theta)/(1-cos theta)-(cos^(2) theta)/(1-sin theta)=cos theta-sin theta

If x = sin theta + cos theta sin 2 theta " and " y = cos theta + sin theta sin 2 theta,"prove that " (x+y)^(2//3) + (x-y)^(2//3) = 2

If x=2 cos theta- cos 2 theta and y=2 sin theta - sin 2 theta, then (dy)/(dx) =