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ELECTROSTATICS OF CONDUCTORS | ELECTRIC FIELD AT SURFACE OF CHARGED CONDUCTOR

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Assertion (A): In a cavity in a conductor, the electric field is zero. Reason (R ): Charges in a conductor reside only at its surface.

A spherical charged conductor has sigma as the surface density of charge. The electric field on its surface is E. If the radius of the sphere is doubled keeping the surface density of charge unchanged, what will be the electric field on the surface of the new sphere -

A spherical charged conductor has surface density of charge as sigma . The electric field intensity on its surface is E . If the radius of the surface is doubled, keeping sigma uncharged, what will be the electric field intensity on the new sphere ?