A stone is projected vertically upwards `y=0` second. The net displacement of stone is zero in time interval between `t=0` second to `t=T` seconds. Pick up the correct statement

A stone is projected vertically upwards y=0 second. The net displacement of stone is zero in time interval between t=0 second to t=T seconds. From time t= T //4 second to t=3T//4 second, the average velocity is zero.

A particle is projected vertically upwards and is at a height h after t_(1) seconds and again after t_(2) seconds then

A stone projected vertically upward moves according to the law s=48t-16t^2 . The time taken by the stone to reach the point of projection is

A stone is projected vertically upwards. Its height h at time t sec is h=(80)t-(16)t^(2) . The velocity with which it hits the ground is

A stone projected vertically upward moves according to the law s = 100t-16t^2 . The maximum height reached is

A stone projected vertically upward moves according to the law s=100t-16t^2 . The acceleration at t=2 sec is

A stone is thrown vertically upwards by a boy. It returns to hs hands in 3 seconds. How high does the stone rise?

Two stones are thrown vertically upwards simultaneously from the same point on the ground with initial speed u_(1) = 30 m//sec and u_(2) = 50 m//sec . Which of the curve represent correct variation (for the time interval in which both reach the ground) of (x_(2) - x_(1)) = the relative position of second stone with respect to first with time (t) (v_(2) - v_(1)) = the relative velocity of second stone with respect to first with time (t). Assuming that stones do not rebound after hitting.