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One end of a string of length 1.5 m is t...

One end of a string of length 1.5 m is tied to a stone of mass 0.4 kg and the other end to a small pivot on a smooth vertical board. What is the minimum speed of the stone required at its lower most point so that the string does not slack at any point in its motion along the vertical circle ?

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One end of string of length 1.5 m is tied to a stone of mass 0.4 kg and the other end to a small pivot on a smooth vertical board. What is the minimum speed of the stone required at its lowermost.point so that the string does not slack at any point in its motion along the vertical circle ?

One end of string of length 2 m , is tied to a body of mass 0.5 kg , the other end is tied to a small nail on a smooth vertical board , what minimum speed should be given to the body at its lowermost point , so that the string does not become slack at any point in its motion along a vertical circular path ? (g=10m//s^(2))

A body of mass 0.4 kg is tied to one end of a string and the other end of the string is tied to a small pivot on a vertical wall . Calculate the minimum speed of the body required at its lower most pint to avoid slacking of string at any point in its motion along the vertical circle of radius 1 m .

STATEMENT-1: One end of a string of length r is tied to a stone of mass m and the other end to a small pivot on a frictionless vertical board. The stone is whirled in a vertical circle with the pivot as the centre. The minimum speed the stone must have, when it is at the topmost point on the circle, so that the string does not slack is sqrt( gR) . because STATEMENT-2: At the topmost point on the circle, the centripetal force is provided partly by tension in the string and partly by the weight of the stone.

STATEMENT-1: One end of a string of length r is tied to a stone of mass m and the other end to a small pivot on a frictionless vertical board. The stone is whirled in a vertical circle with the pivot as the centre. The minimum speed the stone must have, when it is at the topmost point on the circle, so that the string does not slack is sqrt( gR) . because STATEMENT-2: At the topmost point on the circle, the centripetal force is provided partly by tension in the string and partly by the weight of the stone.

A particle of mass m is tied to a light string of length l and rotated along a vertical circular path. What should be the minimum speed at the highest point of its path so that the string does not become slack at any position ?

A stone of mass 0.2 kg is tied to one end of a string of length 80cm Holding the other end, the stone is wirled into a vertical circle. What is the minimum speed of the stone at the lowest point so that it just completes the circle What is the tension in the string at the lowest point of the circular path ? . (g =10^(-2)) .

A small stone of mass 200 g is tied to one end of a string of length 80 cm . Holding the other end in hand , the stone is whirled into a vertical circle What is the minimum speed that needs to be imparted at the lowest point of the circular path , so that the stone is just able to complete the vertical circle ? what would be the tension at the lowest point of circular path ? (Take g = 10 m//s^(2)) .

A small stone of mass 200 g is tied to one end of a string of length 80 cm . Holding the other end in hand , the stone is whirled into a vertical circle What is the minimum speed that needs to be imparted at the lowest point of the circular path , so that the stone is just able to complete the vertical circle ? what would be the tension at the lowest point of circular path ? (Take g = 10 m//s^(2) ) .