Home
Class 13
CHEMISTRY
[" Problem "7.1],[" The following concen...

[" Problem "7.1],[" The following concentrations were "],[" obtained for the formation of "NH_(3)" from "N_(2)],[" and "H_(2)" at equilibrium at "500K" ."],[[N_(2)]=1.5times10^(-2)M.[H_(2)]=3.0times10^(-2)M" and "],[[NH_(3)]=1.2times10^(-2)M" .Calculate equilibrium "],[" constant."]

Promotional Banner

Similar Questions

Explore conceptually related problems

The following concentrations were obtained for the formation of NH_(3) from N_(2) and H_(2) at equilibrium at 500K . [N_(2)]=1.5xx10^(-2)M . [H_(2)]=3.0xx10^(-2) M and [NH_(3)]=1.2xx10^(-2)M . Calculate equilibrium constant.

The following concentrations were obtained for the formation of NH_(3) from N_(2) and H_(2) at equilibrium at 500 K . [N_(2)]=1.5xx10^(-2) M, [H_(2)]=3.0xx10^(-2)M, and [NH_(3)]=1.2xx10^(-2)M . Calculate the equilibrium constant.

The following concentrations were obtained for the formation of NH_(3) from N_(2) and H_(2) at equilibrium at 500 K . [N_(2)]=1.5xx10^(-2) M, [H_(2)]=3.0xx10^(-2)M, and [NH_(3)]=1.2xx10^(-2)M . Calculate the equilibrium constant.

The following concentrations were obtained for the formation of NH_(3) from N_(2) and H_(2) at equilibrium at 500 K . [N_(2)]=1.5xx10^(-2) M, [H_(2)]=3.0xx10^(-2)M, and [NH_(3)]=1.2xx10^(-2)M . Calculate the equilibrium constant.

The following concentration were obtained for the formation of NH_(3) from N_(2) and H_(2) at equilibrium for the reaction N_(2(g))+3H_(2(g))hArr2NH_(3(g)) [N_(2)]=1.5xx10^(-2)M,[H_(2)]=3.0xx10^(-2)M,[NH_(3)]=1.2xx10^(-2)M Calculate the equilibrium constant.

The following concentrations were obtained for the formation of NH_3 from N_2 and H_2 at equilibrium at 500K. [N_2] = 1.5 xx 10^-2M. [H_2] = 3.0 xx10^-2 M and [NH_3] =1.2 xx 10^-2 M . Calculate equilibrium constant.