" &Q "2x^(1/3)+2x^(-1/3)=56866x=-1

(i) (2x+3) (3x-5) (ii) x(1+x)^(3) (iii) (sqrtx + 1/x) (x -1/sqrtx) (iv) (x-1/x)^(2) (v) (x^(2) + 1/x^(2))^(3) (vi) (2x^(2) +5x-1) (x-3)

If P (x) = (x^(3) + 1) (x-1) and Q (x) = (x^(2) -x +1) (x^(2) -3x +2) , then find HCF of P (x) and Q (x) .

Without expanding, find the value of: (i) (x + 1)^4 - 4(x + 1)^3 (x - 1) + 6(x + 1)^2 (x - 1)^2 - 4(x + 1) (x - 1)^3 + (x -1)^4 (ii) (2x - 1)^4 + 4(2x - 1)^3 (3 - 2x) + 6(2x - 1)^2 (3 - 2x)^2 + 4(2x - 1) (3 - 2x)^3 + (3 - 2x)^4

Value of ((x-1)^(3)+(2x-1)^(3)-(3x2)^(3))/((x-1)(2x-1)(3x-2)) is equal to (A)-3(B)0(C)1(D)3

The sum of the polynomials p(x) = x^(3) - x^(2) - 2, q(x) = x^(2) - 3x + 1

The sum of the polynomials p(x) =x^(3) -x^(2) -2, q(x) =x^(2) -3x+ 1

("lim")_(xvec1)((x^4+x^2+x+1)/(x^2-x+1))^(1-"cos"(x+1))/((x+1)^(2))i se q u a lto 1 (b) (2/3)^(1/2) (c) (3/2)^(1/2) (d) e^(1/2)