Home
Class 12
MATHS
find distance of the plane 2x-y+3z=4 fro...

find distance of the plane `2x-y+3z=4` from point `(1,0,-2)`

Promotional Banner

Similar Questions

Explore conceptually related problems

The distance of the plane 2x-y+2z+3=0 from the point (3,2,1) is

The distance of the plane 2x+3y-6z+14=0 from point (3, 0, 1) is :

The distance of the plane 2x - 3y + 6z + 14 = 0 from the point (0, 2, 1) equals :

A plane passes through (1,-2,1) and is perpendicualr to two planes 2x-2y+z=0" and "x-y+2z=4, then the distance of the plane from the point (1,2,2) is

A plane passes through (1, -2, 1) and is perpendicular to two planes 2x - 2y + z=0 and x - y + 2z =4, then the distance of the plane from the point (1,2,2) is

A plane passes through (1,-2,1) and is perpendicualr to two planes 2x-2y+z=0" and "x-y+2z=4, then the distance of the plane from the point (1,2,2) is

A plane passes through (1,-2,1) and is perpendicualr to two planes 2x-2y+z=0" and "x-y+2z=4, then the distance of the plane from the point (1,2,2) is

A plane passes through (1,-2,1) and is perpendicualr to two planes 2x-2y+z=0" and "x-y+2z=4, then the distance of the plane from the point (1,2,2) is

A plane passes through (1,-2,1) and is perpendicualr to two planes 2x-2y+z=0" and "x-y+2z=4, then the distance of the plane from the point (1,2,2) is

A plane passes through (1, -2, 1) and is perpendicular to two planes 2x-2y+z=0 and x-y+2z=4. The distance of the plane from the point (0, 2, 2) is