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[" Find the point on hyperbola "3x^(2)-4...

[" Find the point on hyperbola "3x^(2)-4y^(2)=72" which is "],[" nearest to the straight line "3x+2y+1=0]

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The point on the hyperbola 3x^(2) - 4y^(2) = 72 which is nearest to the line 3x + 2y + 1 = 0 is

Find the point on the curve 3x^(2)-4y^(2)=72 which is nearest to the line 3x+2y+1=0

Find the point on the curve 3x^(2)-4y^(2)=72 which is nearest to the line 3x+2y+1=0 .

Find the points on the curve 3x^(2)-4y^(2)=72 which is nearest t the line 3x+2y+1=0.

[" 24.If "M(x_(0),y_(0))" is the point on the curve "3x^(2)-4y^(2)=72" ,whic "],[" is nearest to the line "3x+2y+1=0" ,then the value "o],[[x_(0)+y_(0)" ) is equal to "," (2) "-3," (3) "9," (4) "-9],[" (1) "3," (3) "]]

Find the point on the curve 3x^2-4y^2=72 which is nearest to the line 3x+2y+1=0.

Find the point on the curve 3x^2-4y^2=72 which is nearest to the line 3x+2y+1=0.

Find the point on the curve 3x^2-4y^2=72 which is nearest to the line 3x+2y+1=0.

Find the point on the curve 3x^2-4y^2=72 which is nearest to the line 3x+2y+1=0.

Find the point of the hyperbola (x^(2))/(24)-(y^(2))/(18)=1 which is nearest to the line 3x+2y+1=0 and compute the distance between the point and the line.