[" If for a positive integer "n," the quadratic equation,"],[x(x+1)+(x+1)(x+2)+...+(x+bar(n-1))(x+n)=10n],[" has two consecutive integral solutions.then "n" is "],[" equal to "]

If,for a positive integer n, the quadratic equation,x(x+1)+(x-1)(x+2)+...+(x+n-1)(x+n)=10n has two consecutive integral solutions,then n is equal to : 10 (2) 11(3) 12 (4) 9

If, for a positive integer n , the quadratic equation, x(x+1)+(x-1)(x+2)+................+(x+ n-1)(x+n)=10 n has two consecutive integral solutions, then n is equal to : (1) 10 (2) 11 (3) 12 (4) 9

If, for a positive integer n , the quadratic equation, x(x+1)+(x-1)(x+2)++(x+ n-1)(x+n)=10 n has two consecutive integral solutions, then n is equal to : 10 (2) 11 (3) 12 (4) 9

If, for a positive integer n , the quadratic equation, x(x+1)+(x-1)(x+2)++(x+ n-1)(x+n)=10 n has two consecutive integral solutions, then n is equal to : (1) 10 (2) 11 (3) 12 (4) 9

If, for a positive integer n , the quadratic equation, x(x+1)+(x-1)(x+2)++(x+ n-1)(x+n)=10 n has two consecutive integral solutions, then n is equal to : (1) 10 (2) 11 (3) 12 (4) 9

Solve (x-1)^(n)=x^(n), where n is a positive integer.

The value of the positve integer n for which the quadratic equation sum_(k=1)^(n)(x+k-1)(x+k)=10n has solutions alpha and alpha+1 for some alpha is

The value of the positive integer n for which the quadratic equation sum_(k=1)^n(x+k-1)(x+k)=10n has solutions alpha and alpha+1 for some alpha is

Solve (x - 1)^n =x^n , where n is a positive integer.