([[1,*3],[-1,-4]]+[[vdots,-2],[-1,1]])[[1,3,5],[2,4,6]]

Evaluate the following : {[[1,3],[-1,-4]]+[[3,-2],[-1,1]]}[[1,3,5],[2,4,6]]

Evaluate the following products: ([(1,3),(-1,-4)] + [(3,-2),(-1,-1)]) [(1,3,5),(2,4,6)]

Evaluate the following: ([(1,3),( -1,-4))]+[(3 ,-2 ),(-1 ,1)]) [(1 ,3,5),( 2 ,4 ,6)]

If A = [(2,2,1), (1,3,1), (1,2,2)] then A^-1+(A-5I) (AI)^2 = (i) 1/ 5 [[4,2, -1], [-1,3,1], [-1,2,4]] (ii) 1/5 [[4, -2, -1], [-1, 3, -1], [-1, -2,4]] (iii) 1/3 [[4,2, -1], [-1,3,1], [-1,2,4]] (iv) 1/3 [[4, -2, -1], [-1,3, -1], [-1, -2,4]]

Show that [[5,-1],[6,7]] [[2,1],[3,4]] ne [[2,1],[3,4]] [[5,-1],[6,7]]

If A=[[2,3,-4],[1,0,6],[-2,1,5]],B=[[5,1,2],[6,-1,4],[5,3,-4]] , find 2A-3B .

If A=[[2,3,-4],[1,0,6],[-2,1,5]],B=[[5,1,2],[6,-1,4],[5,3,-4]] , find 2A-3B .

Show that: [[5,-1],[6,7]][[2,1],[3,4]] ne [[2,1],[3,4]][[5,-1],[6,7]]

Without expanding prove that: |[12, 2, 4, -5, 1],[-8, 1, -5, 2, -1],[6, 4, a ,-3, 2],[-10, 2, 1 ,3 ,4],[-2, 4, 6 ,8, -5]|=|[12, -4, -8, 10, -2],[4, 1, -5, 2, -1],[-3, 4, a, -3, 2],[5, 2, 1, 3, 4],[1, 4, 6, 8, -5]| .

Delta=abs([1xx5,2xx5,3xx5],[3,1,6],[4,2,1]) =5 abs([1,2,3],[3,1,6],[4,2,1])