वक्र `y^(2)=4ax` तथा `ay=2x^(2)` का प्रतिच्छेद कोण होगा-

If x - 2y = 3 and xy = 5, find the value of x^2-4y^2 . यदि x - 2y = 3 तथा xy = 5 है, तो x^2-4y^2 का मान क्या होगा ?

The angle between the curves : y^(2)=4ax and ay=2x^(2) is :

If X^2+Y^2=100 and X : Y= 4 : 3, then what is the value of X^2-Y^2 ? यदि X^2+Y^2=100 तथा X : Y= 4 : 3 है, तो X^2-Y^2 का मान क्या होगा ?

The angle between the curves y^(2)=4ax and ay=2x^(2) is

The area (in square unit ) bounded by the parabolas y^(2) = 4ax and x^(2) = 4ay is -

Two circles x^(2) + y^(2) + ax + ay - 7 = 0 and x^(2) + y^(2) - 10x + 2ay + 1 = 0 will cut orthogonally if the value of a is

Two circles x^(2) + y^(2) + ax + ay - 7 = 0 and x^(2) + y^(2) - 10x + 2ay + 1 = 0 will cut orthogonally if the value of a is

If theta is the angle between the curves y^2=4ax,ay=2x^2 at (a, 2a) , then tantheta =

ax-ay=2;(a-1)x+(a+1)y=2(a^(2)+1)

If the area bounded by y^(2)=4ax and x^(2)=4ay is (64)/(3) square units, then the positive value of a is