The following data are obtained for a reaction, `X+Yrarr"Products"`.
`{:("Expt. ",[X_(0)]//"mol ",[Y_(0)]//"mol ","rate/mol L"^(-1)s^(-1)),(1,0.25,0.25,1.0xx10^(-6)),(2,0.50,0.25,4.0xx10^(-6)),(3,0.25,0.50,8.0xx10^(-6)):}`
The overall of the reaction is

The following data is given at 27^(@)C for the reaction xA+yB rarr product . {:("Trial. ",[A]"mol / L ",[B]"mol/L ","Rate (M s^(-1))),(1,0.01,0.01,10^(-6)),(2,0.01,0.02,2xx10^(-6)),(3,0.04,0.02,32xx10^(-6)):} If reaction is elementary,then select the correct relation. (A) x=y+2 (B) y=x+2 (C)x=y (D) x=y+1

The following data are for the reaction A+B rarr Products: {:(Conc. of A(M),,Conc. of B(M),,Initial rate),(,,,,(mol L^(-1) s^(-1))),(0.1,,0.1,,4.0xx10^(-4)),(0.2,,0.2,,1.6xx10^(-3)),(0.5,,0.1,,1.0xx10^(-2)),(0.5,,0.5,,5.0xx10^(-2)):} (a) What is the order with respect to A and B for the reaction? (b) Calculate the rate constant Determine the reaction rate when the concentrations of A and B are 0.2 M and 0.35 M respectvely.

The experiment data for the reaction 2A + B_(2) rarr 2AB is |{:("Experiment",[A] M,[B_(2)] M,"Initial rate" (mol L^(-1) s^(-1)),),(I,0.50,0.5,1.6 xx 10^(-4),),(II,0.50,1.0,3.2 xx 10^(-4),),(III,1.00,1.0,3.2 xx 10^(-4),):}| Write the most probable rate equation for the reaction giving reason for your answer.

The experiment data for the reaction 2A + B_(2) rarr 2AB is |{:("Experiment",[A] M,[B_(2)] M,"Initial rate" (mol L^(-1) s^(-1)),),(I,0.50,0.5,1.6 xx 10^(-4),),(II,0.50,1.0,3.2 xx 10^(-4),),(III,1.00,1.0,3.2 xx 10^(-4),):}| Write the most probable rate equation for the reacting giving reason for you answer.

The experiment data for the reaction 2A + B_(2) rarr 2AB is |{:("Experiment",[A] M,[B_(2)] M,"Initial rate" (mol L^(-1) s^(-1)),),(I,0.50,0.5,1.6 xx 10^(-4),),(II,0.50,1.0,3.2 xx 10^(-4),),(III,1.00,1.0,3.2 xx 10^(-4),):}| Write the most probable rate equation for the reacting giving reason for you answer.

For a hypothetical reaction A + B rarr C , suggest the rate law and order form the following data: |{:("Experiment",[A] (mol L^(-1)),[B] (mol L^(-1)),"Refer of reaction" (mol L^(-1) s^(-1)),),(I,0.25,0.25,3.0 xx 10^(-3),),(II,0.50,0.25,6.0 xx 10^(-3),),(III,0.50,0.50,1.20 xx 10^(-2),):}|

For a hypothetical reaction A + B rarr C , suggest the rate law and order form the following data: |{:("Experiment",[A] (mol L^(-1)),[B] (mol L^(-1)),"Refer of reaction" (mol L^(-1) s^(-1)),),(I,0.25,0.25,3.0 xx 10^(-3),),(II,0.50,0.25,6.0 xx 10^(-3),),(III,0.50,0.50,1.20 xx 10^(-2),):}|

1.0xx10^(-8)((5*0)/(25))^(2)

In data given below. {:(,[A],[B],"rate"),(,mol//L,mol//L,mol L ^(-1)s^(-1)),(a., 0.02,1.2,3.0xx10^(-3)),(b.,0.04,2.4,6.0xx10^(-3)):} The reaction may be

In data given below. {:(,[A],[B],"rate"),(,mol//L,mol//L,mol L ^(-1)s^(-1)),(a., 0.02,1.2,3.0xx10^(-3)),(b.,0.04,2.4,6.0xx10^(-3)):} The reaction may be