A helium nucleus is moving in a circular path of radius 0.8m. If it takes 2s to complete one revolution. Find out magnetic field produced at the centre of the circle:

When a helium nucleus revolves in a circular orbit of radius 0.8 m,if it takes 2 sec to comlete one revolution. find magnetic field produced at the centre would be _____ T.

A particle having charge 100 times that of an electron is revolving in a circular path of radius 0.8m with one rotation per second. The magnetic field produced at the centre is

A particle having charge 100 times that of an electron is revolving in a circular path by radius 0.8 m with one rotation per second. The magnetic field produced at the centre is,

An electron moving in a circular orbit of radius makes n rotations per second. The magnetic field produced at the centre has magnitude :

An electron moving in a circular orbit of radius makes n rotations per second. The magnetic field produced at the centre has magnitude :

A body moves on a circular path of radius 1 m. It completes one circle in 2 seconds. Find its speed.

A helium nucleus makes a full rotation in a circle of radius 0.8 metre in two seconds. The value of the magnetic field B at the centre of the circle will be

A helium nucleus makes a full rotation in a circle of radius 0.8 metre in two seconds. The value of the magnetic field B at the centre of the circle will be