[" A physical quantity "P=((sqrt(abc^(2))))/(d^(3)e^(1/3))" is determined "],[" by measuring "a,b,c,d" and "e" separately with "],[" the percentage error of "2%,3%,2%,1%" and "],[6%" respectively.Minimum amount of error is "]

A physical quantity P=sqrt(abc^2)/d^3 is determined by measuring a,b,c and d seperately with the percentage error of 2% , 3% , 2% and 1% respectively. Minimum amount of error is contributed by the measurement of

If P=a^2*b^3*c*d^1/2 and the percentage error in a,b,c and d are 1%,2%,3% and 4% respectively.Find percentage error in P.

A physical quantity is given by X=(a^(2)sqrt(b))/c^(3) . If the percentage errors of measurement in a, b and c are 3%, 2% and 1% respectively, then the percentage error in X is

In the measurement of a physical quantity X = (A^(2) B)/(C^(1//3) D^(3)) . The percentage erros introduced in the measurments of the quantities A,B,C and D are 2%,2%,4% and 5% respectively. Then the minimum amount of percentage of error in the meaurement fo X is contributed by

In the measurement of a physical quantity X = (A^(2)B)/(C^(1//3)D^(3)) . The percentage errors introduced in the measurement of the quantites A,B,C and D are 1%, 3% , 4% and 5% respectively . Then the minimum amount of percenatage of error in the measurment of X is contributed by

In the measurement of a physical quantity X = (A^(2)B)/(C^(1//3)D^(3)) . The percentage errors introduced in the measurement of the quantites A,B,C and D are 1%, 3% , 4% and 5% respectively . Then the minimum amount of percenatage of error in the measurment of X is contributed by

A physical quantity P = a^3b^2/cd . If the percentageerrors in the measurement of a, b, c and d are 1%, 2%, 3% and 4% then the percentage error in P______.

A physical quantity P=(a^(3)b^(2))/(sqrt(cd)) the percentage errors in measurement in a,b,c,d are 1%, 3%,4% and 2% respectively. What is the percentage error in measurement of quantity P?