A coil is connected to a battery of `12 V` emf and negligible resistance. The current in the solenoid grows to `63%` of its final steady state value in `0.3 s`. If the final steady state current is `0.6A`, the inductance of the solenoid is

A coil resistance R and inductance L is connected to a battery of emf E volt. The final current in the coil is

A coil of inductance 300mH and resistance 2 Omega. The current reaches half of its steady state value in

A solenoid is connected to a battery so that a steady current flows through it. If an iron core is inserted into the solenoid, then

A solenoid is connected to a battery so that a steady current flows through it. If an iron core is inserted into the solenoid, then

A coil of self inductance 2.5 H and resistance 20 Omega is connected to a battery of emf 120 V having internal resistance of 5 Omega . Find : The current in the circuit in steady state.

An inductor with an inductance of 2.5H and a resistance of 8Omega is connected to the terminals of a battery with an EMF 6V and negligible internal resistance. Find (a) The initial rate of increase of current in the circuit (b) The rate of increase of current at the instant when the current is 0.50A (c ) The current 0.25s after the circuit is closed (d) The final steady state current

A coil of resistance 40 Omega is connected across a 4.0 V battery. 0.10 s after the battery is connected, the current in the coil is 63 mA. Find the inductance of the coil.