A fighter plane moving with a speed of `50 sqrt(2) m s^-1` upward at an angle of `45^@` with the vertical releases a bomb when it was at a height `1000 m` from ground. Find (a) the time of flight
(b) the maximum height of the bomb above ground.

A bomber diving at an angle of 30^@ with the horizontal releases a bomb at a height of 980m. The bomb is observed to strike the ground 4 s after it's release. What was the velocity of the bomber in m/s?

A balloon is going upwards with a velocity of 20 m It releases a packet when it is at a height of 160 m from the ground. The time taken by the packet to reach the ground is

A bomber flying upward at an angle of 53^(@) with the vertical releases a bomb at an altitude of 800 m .The bomb strikes the ground 20 s after its release.If g=10ms^(-2) , the velocity at the time of release of the bomb in ms^(-1) is

A Bomber flying upward at an angle of 53^(@) with the vertical releases a bomb at an altitude of 800 m. The bomb strikes the ground 20 s after its release. Find : [Given sin 53^(@)=0.8, g=10 m//s^(2) ] (i) The velocity of the bomber at the time of release of the bomb. (ii) The maximum height attained by the bomb. (iii) The horizontal distance tranvelled by the bomb before it strikes the ground (iv) The velocity (magnitude & direction) of the bomb just when it strikes the ground.

A Bomber flying upward at an angle of 53^(@) with the vertical releases a bomb at an altitude of 800 m. The bomb strikes the ground 20 s after its release. Find : [Given sin 53^(@)=0.8, g=10 m//s^(2) ] (i) The velocity of the bomber at the time of release of the bomb. (ii) The maximum height attained by the bomb. (iii) The horizontal distance tranvelled by the bomb before it strikes the ground (iv) The velocity (magnitude & direction) of the bomb just when it strikes the ground.

A Bomber flying upward at an angle of 53^(@) with the vertical releases a bomb at an altitude of 800 m. The bomb strikes the ground 20 s after its release. Find : [Given sin 53^(@)=0.8, g=10 m//s^(2) ] (i) The velocity of the bomber at the time of release of the bomb. (ii) The maximum height attained by the bomb. (iii) The horizontal distance tranvelled by the bomb before it strikes the ground (iv) The velocity (magnitude & direction) of the bomb just when it strikes the ground.

A particle is projected with a speed of 10 m/s at an angle 37^(@) with the vertical. Find (i) time of flight (ii) maximum height above ground (iii) horizontal range.

A particle is projected with a speed of 10 m/s at an angle 37^(@) with the vertical. Find (i) time of flight (ii) maximum height above ground (iii) horizontal range.

A particle is projected with a speed of 10 m/s at an angle 37^(@) with the vertical. Find (i) time of flight (ii) maximum height above ground (iii) horizontal range.