If there is an error of 2% in measuring its length, of a simple pendulum then the percentage error in the period will be

If there is an error of 2% in measuring the length of simple pendulum, then percentage error in its period is: 1% (b) 2% (c) 3% (d) 4%

If there is an error of 2% in measuring the length of simple pendulum, then percentage error in its period is: (a) 1% (b) 2% (c) 3% (d) 4%

If there is an error of 2% in measuring the length of simple pendulum,then percentage error in its period is: (a) 1% (b)2% (c) 3% (d) 4%

There is 4% error in measuring the period of a simple pendulum. The approximate percentage error in length is …….. Hint : T = 2pi sqrt((l)/(g))

If the length of a simple pendulum is decreased by 3%, then the percentage error in its period T is

If the length of a simple pendulum is decreased by 2%, find the percentage error in its period T.

In case of measurement of 'g' if error in measurement of length of pendulum is 2%, the percentage error in time period is 1 %. The maximum error in measurement of g is

In case of measurement of 'g' if error in measurement of length of pendulum is 2%, the percentage error in time period is 1 %. The maximum error in measurement of g is

If there is 2% error in measuring the radius of sphere, then…………… will be the percentage error in the surface area.

There is an error of 2% in the measurement of side of a cube. The percentage error in the calclation of its volume will be :