A bullet of mass 10 g moving with a velocity of 400 m/s gets embedded in a freely suspended wooden block of mass 900 g. What is the velocity acquired by the block ?

A bullet of mass 20 gram moving with a velocity of 300m//s gets embedded in a freely suspened wooden block of mass 880 gram . What is the velocity acquired by the blocks?

A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M . If the block rises to a height h , the initial velocity of the block will be (

A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M . If the block rises to a height h , the initial velocity of the block will be ?

A bullet of mass 250g , moving with a horizontal velocity of 400 m*s^(-1) , gets embedded in a target. The target of mass 4.75 kg can move freely. Find the loss of kinetic energy due to this collision. What happens to this energy loss ?

A bullet of mass 0.05 kg moving with velocity 400 m/s gets embedded after collision with a block of mass 3.95 kg placed on a smooth horizontal platform as shown in the figure. If height of the platform from the ground is 20 m and block strikes the ground at B, then the value of AB is

A bullet of mass m, moving with a velocity u stikes a suspended wooden block of mass M. If the block rises to a height h , the initial velocity will be given by .

A bullet of mass 50 g , moving with a velocity of 50 m*s^(-1) hits and enters a wooden block of mass 2kg and comes to rest within it. The wooden block was initially at rest on a smooth table. Find the final velocity of the wooden block. What are the initial and final kinetic energies of the block-bullet system?