Number of electrons in 36mg of `._8^(18)O^(-2)` ions are : (Take `N_(A) = 6 xx 10^(23))`

Number of electrons present in 3.6 mg of NH_(4)^(+) are : (N_(A) = 6 xx 10^(23))

Number of electrons present in 3.6 mg of NH_(4)^(+) are : (N_(A) = 6 xx 10^(23))

Total number of protons, neutrons and electrons present in 14 mg of ._(6)C^(14) is : (Take N_(A) = 6 xx 10^(23))

Number of electrons in 1.8 grams of H_(2)O are

" Number of mole of electrons in 8g O^(2-) ions are "

One atom of an element X weighs 6 xx 10^(-23) gm . Number of moles of atoms in 3.6 kg of sample of X will be : (N_(A) = 6 xx 10^(23))

One atom of an element X weighs 6 xx 10^(-23) gm . Number of moles of atoms in 3.6 kg of sample of X will be : (N_(A) = 6 xx 10^(23))