If `cosec x=1+cotx` then `x=2npi, 2 npi+pi/2`

If "cosec"x=1+cotx , then x=2npi,2npi+(pi)/(2)

If "cosec"x=1+cotx , then x=2npi,2npi+(pi)/(2)

If cosecx=1+cotx, then x=2npi,2npi+(pi)/(2),ninZ .

The general solution of the trigonometric equation sinx+cosx=1 is given by x=2npi,n0,+-1,+-2 x=2npi+pi/2; n=0,+-1,+-2, dot x=npi+(-1)^npi/4-pi/4n=0,+-1,+-2, non eoft h e s e

The general solution of the trigonometric equation sinx+cosx=1 is given by x=2npi,n0,+-1,+-2 x=2npi+pi/2; n=0,+-1,+-2, dot x=npi+(-1)^npi/4-pi/4n=0,+-1,+-2, non eoft h e s e

The roots of the equation, cotx- cos x=1- cotx*cos x are : (i)npi+pi/4 (ii)2npi+pi/4 (iii)npi+pi/4 or 2npi+-pi (iv) (4n+1)pi/4 or(2n+1)pi; n in I

The general solution of cosxcos6x=-1 is x=(2n+1)pi,n in Z x=2npi,n in Z x=npi,n in Z (d) none of these

The general solution ofthe trigonometrical equation sinx+cosx=1 for n=0, +- 1, +-1 is given by (a) x=2npi (b) x=2npi+pi/2 (c) x=npi+(-1)^npi/4-pi/4 (d) non of these

If the line xcostheta+ysintheta=P is the normal to the curve (x+a)y=1, then show theta in (2npi+pi/2,(2n+1)pi)uu(2npi+(3pi)/2,(2n+2)pi),n in Z

If the line xcostheta+ysintheta=P is the normal to the curve (x+a)y=1, then show theta in (2npi+pi/2,(2n+1)pi)uu(2npi+(3pi)/2,(2n+2)pi),n in Z