Given a regular hexagon ABCDEF with centre O, show that `vecOB-vecOA=vecOC-vecOD`

Given a regular hexagon ABCDEF with centre o,show that vec OB-vec OA=vec OC-vec OD

In a regular hexagon ABCDEF,vec AE

In a regular hexagon ABCDEF, vec(AE)

In a regular hexagon ABCDEF, vec(AE)

Let O be the centre of a regular hexagon ABCDEF. Find the sum of the vectors vec OA,vec OB,vec OC,vec OD,vec OE and vec OF .

Consider the regular hexagon ABCDEF with centre at O (origin). Five forces vec(AB), vec(AC), vec(AD), vec(AE), vec(AF) act at the vertex A of a regular hexagon ABCDEF. Then their resultant is

Consider the regular hexagon ABCDEF with centre at O (origin). Five forces vec(AB), vec(AC), vec(AD), vec(AE), vec(AF) act at the vertex A of a regular hexagon ABCDEF. Then their resultant is -

Lẹt 0 be the centre of the regular hexagon ABCDEF. Find the sum of the vectors 'vec(O A)+vec(O B)+vec(O C)+vec(O D)+vec(O E)+vec(O F)'

Consider the regular hexagon ABCDEF with centre at 0 (origin),then if vec (AD)+vec (EB)+vec (FC) is equal to k(vec (AB)) .then k is

Consider the regular hexagon ABCDEF with centre at O (origin). vec(AC)+vec(DE) is equal to -