A uniform wound solenoid coil of self inductance `1.8 xx 10^(-4) H` and resistance ohm is broken into two identical coils. These indentical coils are connected in parallel across a 12 V battery of negligible resistance. Calculate the steady state current through the battery and time constant of the circuit.

A uniformly wound solenoid coil of self inductance 1.8xx10^(-4)H and resistance 6Omega is broken up into two identical coils. These identical coils are then connected in parallel across a 12V battery of negligible resistance. The time constant and steady state current will be

A uniformly wound solenoid coil of self inductance 1.8xx10^(-4)H and resistance 6Omega is broken up into two identical coils. These identical coils are then connected in parallel across a 12V battery of negligible resistance. The time constant and steady state current will be

A uniform wound solenoidal coil of self inductance 1.8xx10^(-4) henry and resistance 6 ohm is broken up into two identical coils. These identical coils are then connected in parallel across a 15-volt battery of negligible resistance. The time constant for the current in the circuit is.......seconds and the steady state current through the battery is ..............amperes.

A uniform wound solenoidal coil of self inductance 1.8xx10^(-4) henry and resistance 6 ohm is broken up into two identical coils. These identical coils are then connected in parallel across a 15-volt battery of negligible resistance. The time constant for the current in the circuit is.......seconds and the steady state current through the battery is ..............amperes.

A uniformly wound solenoid coil of slf inductnace 4 mH and resistance 12 Omega is broken int two parts. These two coil are connected in parallel across is 12V battery. The steady current through battery is

A uniformly wound solenoid coil of slf inductnace 4 mH and resistance 12 Omega is broken int two parts. These two coil are connected in parallel across is 12V battery. The steady current through battery is

Self - inductance 0.8xx10^(-4) H of a uniformly wound solenoid, having resistance 3 Omega is broken up into two indentical coils. Those coils are connected in series across a 6 V battery of negligible resistance. Find time constant and steady state current.

Self - inductance 0.8xx10^(-4) H of a uniformly wound solenoid, having resistance 3 Omega is broken up into two indentical coils. Those coils are connected in series across a 6 V battery of negligible resistance. Find time constant and steady state current.

Two resistors 4 Omega and 6 Omega connected in parallel. The combination is connected across a 6 V battery of negligible resistance. Calculate (a) the current through the battery (b) current through each resistor.

Two resistors of 4 Omega and 6 Omega are connected in parallel. The combination is connected across a 6 V battery of negligible resistance. (i) Draw a circuit diagram. (ii) Calculate :the current through the battery