बिन्दु `(-1,3,-2)` से होकर जाने वाली उस रेखा का समीकरण ज्ञात कीजिए जो रेखाओ `x/1 =y/2 = z/3` और `(x+2)/(-3)=(y-1)/2 =(z+1)/5` पर लम्बवत है।

The lines x/2=y/1=z/3 and (x-2)/(2)=(y+1)/(1)=(3-z)/(-3) are ….

यदि (x/3+1,y-2/3) = (5/3,1/3) हो, तो x और y का माना ज्ञात , कीजिये।

The lines (x-2)/(1)=(y-3)/(2)=(z-4)/(3) and (x-1)/(-5)=(y-2)/(1)=(z-1)/(1) are

(x+1)/(3)=(y+2)/(1)=(z+1)/(2) and (x-2)/(1)=(y+2)/(2)=(z-3)/(3)

The lines (x-2)/(1)=(y-3)/(2)=(z-4)/(3)and(x-1)/(-5)=(y-2)/(1)=(z-1)/(1) are

The lines (x-1)/(3) = (y+1)/(2) = (z-1)/(5) and x= (y-1)/(3) = (z+1)/(-2)

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

2x-3z + w = 1x-y + 2w = 1-3y + z + w = 1x + y + z = 1

x+y-z=1 3x+y-2z=3 x-y-z=-1