`(7)/(x)+(3)/(5)=(-1)/(10)`

Arrange the following in ascending order : (1)/(5),(3)/(7),(7)/(10)

[[1,0,-13,4,50,-6,-7]]=[[(1)/(10),(3)/(10),(1)/(5)(21)/(20),-(7)/(20),-(2)/(5)-(9)/(10),(3)/(10),(1)/(5)]]

Let f(x)=(x+1)/(2x-1) and g(x)=|x|+1 Then the number of elements in the set {x:f(x)>=g(x)}*[((1)/(2),(3)/(5))uu((3)/(5),(7)/(10))uu((7)/(10)uu(4)/(5))uu((4)/(5),1)]

5(1)/(7)-{3(3)/(10)-:(2(4)/(5)-(7)/(10))}

(3^((1)/(5)))^(x)+(3^((1)/(10)))^(x-10)=84

Solve : (3)/(5)(4x-9) - (5)/(4)(3x-8) = 5-(7)/(10)(2x-1) .

(x-4)/(x-5)+(x-6)/(x-7)=(10)/(3)

Simplify : i. (1 (5)/(7) xx (7)/(10) ) - ((3)/(5) div (9)/(10))