If `f: R to R` be defined by `f(x)={(2x:xgt3),(x^(2):1lt x le 3),(3x:x le 1):}`
Then,`f(-1)+f(2)+f(4)` is

Let f:R rarr R be defined by f(x)={{:(2x, xgt3),(x^2,1lexlt3),(3x,xle1):} Then f(-1)+f(2) +f(4) is

Let f : R rarrR be defined by f(x)={{:(2x ,,,x gt3 ),(x^2,,,1 lt xle3),(3x,,,x le1):} Then f(-1) + f(2) + f(4) is

f : R rarr R , f(x) ={{:(2x,xgt3),(x^2,1ltxle3),(3x,xle1):} then find f (-1) + f(2) + f(4) .

If f: R to R defined by f(x) ={{:(2x+5, if, x gt 0),(3x-2, if, x le 0):} then f is

If the function f : R to R is defined by f(x)={{:(2x+7","x lt -2),(x^(2)-2","-2 le x lt 3","),(3x-2","x ge 3):} then find the values of (i) f(4) (ii) f(-2) (iii) f(4)+2f(1) (iv) (f(1)-3f(4))/(f(-3))

If f: R to R is defined by: f(x-1) =x^(2) + 3x+2 , then f(x-2) =

If the function f: R to R is defined by f (x) {:{( 2x+1 ,xlt-1) ,( x^(2) -1,le x lt 3 ),( 3x-2, xge 3) :} "Find " (f(-1) +f(3))/( 2)

If f: R to R is defined by f(x) = {(x-1, ",","for"x le 1),(2-x^(2), ",", "for"1 lt x le 3 ),(x-10, ",", "for"3 lt x lt 5 ),(2x, ",", "for"x ge 5 ):} then the set of points of discontinuity of f is