The continued product `2.6.10.4…..`(`n` times) in equal to

The continued product 2.6.10.14….. ( n times) in equal to

the continued product 2.6.10.14... to n factors is equal to 2np_(n)(b)^(2n)C_(n)(n+1)(n+2)(n+3)...(n+n)2^(n)*(1.3.5......2n-1)

The sum of two positive quantities is equal to 2n. The probabilities that their product is not less than 3/4 times their product when they are equal is

The sum of two positive quantities is equal to 2n .the probability that their product is not less than 3/4 xx their greatest product is a.3/4 b.1/4 c.1/2 d.none of these

Express the product of 3.2xx10^(6) and 4.1xx10^(-1) in the standard form.

The solubility product of BaSO_4 is 4 xx 10^(-10) . The solubility of BaSO_4 in presence of 0.02 N H_2SO_4 will be

The solubility product of BaSO_4 is 4 xx 10^(-10) . The solubility of BaSO_4 in presence of 0.02 N H_2SO_4 will be

Find the product : {(-10)xx(-5)}xx6