The displacement of a particle after time t is given by `x = (k // b^(2)) (1 - e^(-bi))`. Where b is a constant. What is the acceleration fo the particle ?

The displacement of a particle after time is given by x = k/b^2 (1-e^(-bt)) where 'b' is a constant. The acceleration of the particle is

The displacement of the particle along a straight line at time t is given by X=a+bt+ct^(2) where a, b, c are constants. The acceleration of the particle is

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

The displacement of a particle moving in a straight line, is given by s = 2t^2 + 2t + 4 where s is in metres and t in seconds. The acceleration of the particle is.

The linear momentum of a particle as a fuction of time 't' is given by , p = a +bt , where a and b are positive constants . What is the force acting on the particle ?

The linear momentum of a particle as a fuction of time 't' is given by , p = a +bt , where a and b are positive constants . What is the force acting on the particle ?

Displacement (x) of a particle is related to time (t) as x = at + b t^(2) - c t^(3) where a,b and c are constant of the motion. The velocity of the particle when its acceleration is zero is given by: