(dy)/(dx)=y tan x;y=2" यदि "x=0...

(dy)/(dx)=y tan x;y=2" यदि "x=0

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(dy)/(dx)=y tan x , y=1 when x=0

(dy)/(dx) = y tan x, y = 1 when x = 0

(dy)/(dx) = y tan x, y = 1 when x = 0

(dy)/(dx) = y tan x, y = 1 when x = 0

(dy)/(dx) = y tan x, y = 1 when x = 0

Solve (dy)/(dx)+y tan x=y^(2)sec x

Solve (dy)/(dx)+y tan x=y^(2)sec x

Solve (dy)/(dx)+y tan x=y^(2)sec x

If (dy)/(dx)+y tan x=sin2x and y(0)=1, then y(pi) is equal to:

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