" (iv) "2y^(3)+y^(2)-2y-1

Factorise : - 2y^(3)+y^(2)-2y-1

Subtract : 5y^(4) - 3y^(3) + 2y^(2) + y - 1 from 4y^(4) - 2y^(3) - 6y^(2) - y + 5

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))

If y=(sqrt(3)+1)/(2) then find the value of 4y^(3)+2y^(2)-8y+10=

Subtract: (-2y^(2)+(1)/(2)y-3) om 7y^(2)-2y+10

((y^(3)-3y^(2)+5y-1)/(y-1))

Factorise : 2y^3+y^2-2y-1 .