The direction ratios of the line `x+1=2y=-12z` are
(1) (6,6,-1) (2) (12,6,1) (3) (6,-6,1) (4) (12,6,-1)

Find the directions ratios of the line perpendicular to the lines (x-7)/(2) = ( y+ 7)/(-3) =(z-6)/(1) and (x+5)/(1) = (y+3)/(2)= (z-6)/(-2)

Direction-ratios of line given by : (x -1)/(3) = (2y + 6)/(10) = (1 -z)/(-7) are ,

The lines x/1=y/2=z/3 and (x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6) are

The lines x/1=y/2=z/3 and (x-1)/(-2)=(y-2)/(-4)=(z-3)/(6)are

The shortest distance between the line 1+x=2y=-12z and x=y+2=6z-6 is

(1)/(3)(3y-12)=6-2(y-1)

The shortest distance between the lines x+a=2y=-12z and x=y+2a=6z-6a is

The point of interesection of the line x = y = z with the plane x + 2y + 3z = 6 is (1,1,-1).

The square of the distance of the point of intersection of the line and the plane (x-1)/(2)=(y-2)/(3)=(z+1)/(6) and the plane 2x-y+z=6 from the point (- 1, -1, 2) is_________