Given two fixed points `A` and `B` and `AB=6` .Then simplest form of the equation to thelocus of such that `PA+PB=8` is

A(2,3),B(2,-3) are two points.The equation to the locus of P. such that PA+PB=8

If A(1,3) and B(2,1) are points,find the equation of the locus of point P such that PA=PB

A point moves in a plane so that its distances PA and PB from two fixed points A and B in the plane satisfy the relation PA-PB=k(k ne 0) , then the locus of P , is

If A and B are two fixed points and P is a variable point such that PA+PB=4, the locus of P is

A(0,4),B(0,-4) are two points.The locus of P which moves such that |PA-PB|=6 is

A(2,3) , B(-2,3) are two points.The locus of p which moves such that PA-PB=4 is

A and B are fixed points of PA+PB=K (constant) and K>AB then the locus of P is

A(2,3),B(-2,3) are two points.The locus of P which moves such that PA-PB=4

Statement I Let A-= (0,1) and B -= (2,0) and P be a point on the line 4x+3y+9=0 then the co - ordinates of P such that |PA -PB| is maximum is (-12/5,17/5) Statement II |PA - PB | le |AB|