Equation of the ellipse with foci `(pm4,0)` and length of latusrectum `(20)/(3)`is

If the equation of the ellipse with foci (pm4 ,0) and length of latus rectum (20)/(3) is (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 then (1)/(2)|a^(2)-b^(2)| is equal to

If the equation of the ellipse with foci (+-4, 0) and length of latus rectum (20)/(3) is (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 then (1)/(2)|a^(2)-b^(2)| is equal to

The equation of the curve whose vertex is (0,0) and length of latusrectum is (16)/(3) , is

Find the equation of the ellipse whose foci are (pm4,0) and eccentricity is (1)/(3) .

The equation of the ellipse with foci (pm 2, 0) and eccentricity =1/2 is

Find the equation of the ellipse whose foci are (pm2,0) and eccentricity is (1)/(3) .

The equation of the ellipse whose foci are (pm5,0) and one of its directrix is 5x= 36 is

Find the equation of the ellipse whose foci are (0,pm3) and eccentricity is (3)/(5) .

Find the equation of the ellipse whose foci are (0,pm1) and eccentricity is (1)/(2) .