Circle `x^(2)+y^(2)+6x+4y+4=0` is reflected in a line mirror and reflected circle have equation `x^(2)+y^(2)+8x+6y+16=0,` then equation of mirror is

Two circles have equations x^(2)+y^(2)-4x-6y-7=0 and x^(2)+y^(2)-2x-3=0 then

(i) Find the equation of a circle , which is concentric with the circle x^(2) + y^(2) - 6x + 12y + 15 = 0 and of double its radius. (ii) Find the equation of a circle , which is concentric with the circle x^(2) + y^(2) - 2x - 4y + 1 = 0 and whose radius is 5. (iii) Find the equation of the cricle concentric with x^(2) + y^(2) - 4x - 6y - 3 = 0 and which touches the y-axis. (iv) find the equation of a circle passing through the centre of the circle x^(2) + y^(2) + 8x + 10y - 7 = 0 and concentric with the circle 2x^(2) + 2y^(2) - 8x - 12y - 9 = 0 . (v) Find the equation of the circle concentric with the circle x^(2) + y^(2) + 4x - 8y - 6 = 0 and having radius double of its radius.

The equation of a circle, which is mirror change of the circle x ^(2) + y ^(2) - 2x =0, in the line, y =3 -x is

Let the equation of circle is x^(2) + y^(2) - 6x - 4y + 9 = 0 . Then the line 4x + 3y - 8 = 0 is a

Find the equation of the image of the circle x^(2)+y^(2)+8x-16+64=0 in the line mirror x=0.

Let the equation of circle is x ^(2) + y ^(2) - 6x + 4y + 12=0. Then the line 3x - 4y + 5 is a

The equation of the image of the circle x^(2)+y^(2)+16x-24y+183=0 by the line mirror 4x+7y+13=0 is :

The equation of the image ofthe circle x^(2)+y^(2)+16x-24y+183=0 by the line mirror 4x+7y+13=0 is