Find `dy/dx` `"x=a cos^(4)theta;y=b sin^(4)theta`

Eliminate theta from x=a cos^(4)theta,y=b sin^(4)theta

Eliminate theta from x=a cos^(4)theta , y=b sin^(4)theta .

if x=a cos^(4) theta, y= a sin^(4) theta, "then" (dy)/(dx)"at" theta=(3pi)/(4) is

Find (dy)/(dx), when x=a cos theta and y=b sin theta

Find (dy)/(dx) if x=3 cos theta- 2cos^(3)theta,y=3 sin theta -2sin^(3) theta.

If x = a cos^(2) theta, y = b sin^(2) theta " then "(dy)/(dx)= ?

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=a cos theta,y=b cos theta

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=cos theta-cos2 theta,y=sin theta-sin2 theta

If x=a cos^(2)theta,y=b sin^(2)theta find (d^2y)/dx^2

Find (dy)/(dx), when x=a(cos theta+theta sin theta) and y=a(sin theta-theta cos theta)