Equation of SHM of a particle is `x=5cos(pi/2t)` ,where x is in cm and t is in second Then average speed of particle in first five second of motion will be?

The equation of motion of a particle started at t=0 is given by x=5sn(20t+pi/3) , where x is in centimetre and t in second. When does the particle a. first come rest b. first have zero acceleration c. first have maximum speed?

The displacement of a partcle is given by x=(t-2)^(2) where x is in metre and t in second. The distance coverred by the particle in first 3 seconds is

The equation of motion of a particle started at t=0 is given by x=5sin(20t+pi//3) where x is in centimeter and t in second. When does particle (a) first come to rest (b) first have zero acceleration (c) first have maximum speed?

The position x of a particle varies with time t as x = 6 + 12t - 2 t^2 where x is in metre and in seconds. The distance travelled by the particle in first five seconds is

The equation of motion of a particle starting at t=0 is given by x=5sin(20t+π/3) , where x is in centimeter and t is in second. When does the particle come to rest for the second time?

The displacement of a particle is moving by x = (t - 2)^2 where x is in metres and t in second. The distance covered by the particle in first 4 seconds is.

x - t equation of a particle in SHM is x = (4 cm)cos ((pi)/(2)t) Here , t is in seconds. Find the distance travelled by the particle in first three seconds.

The equation of motion of a particle is x=a " cos"(alpha t)^(2) . The motion is

The equation of motion for an oscillating particle is given by x = 3 sin 4pi t + 4 cos pi t where x is in mm and t is in second. The particle

The x -coordinate of a particle moving along x -axis varies with time as x=6-4t+t^(2), where x in meter and t in second then distance covered by the particle in first 3 seconds is