हल करें -
`(4x-1)(x+2)=2+7x`

निम्नलिखित समीकरणों को गुणनखंड विधि द्वारा हल करें- (2x)/(x-3)+1/(2x+3)+(3x+9 )/((x-3)(2x+3))=0

4x^2-7x-2=0

If x ^(3) - 7x + 4 is divided by (x-1), (x +2) and (2x +1), then the find the respective remainders.

Factorise : x^(2) + (1)/(4x^(2)) + 1 - 7x - (7)/(2x)

(3 x^2 - 7x + 1) (4x - 4x) = ____

If |x| is so small that x^2 and higher powers of x many be neglected , prove that ((1 + 7x)^(2/3) . (1 - 4x)^(-2))/((4 + 7x)^(1/2)) = 1/2 (1 + 283/24 x)

If |x| is so small that x^2 and higher powers of x many be neglected , prove that ((1 + 7x)^(2/3) . (1 - 4x)^(-2))/((4 + 7x)^(1/2)) = 1/2 (1 + 283/24 x)

Check whether the following are quadratic equations : (1) (x-3)^(2)=x(2x-5) (2) (2x-3)(8x+1) = (4x+5)(4x-5) (3) (5x+3)(x-2)=(4x+3)(2x-1) (4) (2x+5)^(3)=8(x-1)^(3) (5) x^(2)+7x-8=x(x+5) (6) x^(3)+9x^(2)-7x+2=(x+3)^(3)

Solve for x : 2/5 (4x-1)-[4x-((1-3x)/2)]=(x-7)/2