(x)/(1+2i)+(y)/(3+2i)=(5+6i)/(8i-1)

Solve ((1-i)x+3i)/(2+i)+((3+2i)y+i)/(2-i)=-i "where" x, y, in R.

(-i)(2i)(-(1)/(8)i)^(3)

Perform the indicated operations and write the result in the form x+iy: (i) (-3+2i)+(-6+3i) (ii) ((1)/(2)+(7)/(2)i)-(4+(5)/(2)i) (iii) (1-2i)-i+(4-7i)-2i+(5i+3) .

1/(6i)+1/(7i)=x/(8i)

Express the following in the form of a + b i :(i) (-5i)(1/8i) (ii) (-i)(2i)(-1/8i)^3

Express the following in the form of a" "+" "b i : (i) (-5i)(1/8i) (ii) (-i)(2i)(-1/8i)^3

Express the following in the form of a+bi, (i) (-5i) (1/8 i) , (ii) (-i)(2i)(-1/8i)^(3)

Express the following in the form of a+bi, (i) (-5i) (1/8 i) , (ii) (-i)(2i)(-1/8i)^(3)

Express the following in the form of a+bi, (i) (-5i) (1/8 i) , (ii) (-i)(2i)(-1/8i)^(3)