cot^(-1)x-cot^(-1)(x+2)=(pi)/(12)

Solve cot^(-1)x-cot^(-1)(x+2)=(pi)/(2),xgt0

Solve : cot^(-1)2x+cot^(-1)3x=(pi)/(4)

If sin^(-1)x+cot^(-1)(1/2)=(pi)/(2), " then : " x=

The solution set of inequality (cot^(-1)x)(tan^(-1)x)+(2-(pi)/(2))cot^(-1)x-3tan^(-1)x-3(2-(pi)/(2))>0 is (a,b), then the value of cot ^(-1)a+cot^(-1)b is

tan^(-1) x +cot^(-1)x =(pi)/(2) holds, when

cot ^(-1)""x+cot^(-1)""2x=(3pi)/(4)

If cot^(-1)x+cot^(-1)y+cot^(-1)z=(pi)/(2) , then x+y+z=

If cot^(-1)x+cot^(-1)y+cot^(-1)z=(pi)/(2) , then x+y+z=

If cot^(-1)x+cot^(-1)y+cot^(-1)z=(pi)/(2) , then x+y+z=