Home
Class 12
CHEMISTRY
17 AH = 58.04 kJ for the process of deco...

17 AH = 58.04 kJ for the process of decomposition of N204 And AS = 176.7 Joule / Kelvin, then AG = ... T Take = 298 K.

Promotional Banner

Similar Questions

Explore conceptually related problems

Gaseous N_(2)O decomposes at 298 K and forms N_(2)(g) and O_(2)(g) .The DeltaH for the reaction at 1 atm pressure and 298 K is -163.15 kJ . What is the value of DeltaU for the decomposition of 200 g of N_(2)O under the same conditions?

The standard enthalpy or the decomposition of N_2 O_5 to NO_2 is 58.04 kJ and standard entropy of this reaction is 176.7 J/K. The standard free energy change for this reaction at 25^@ C is_____________.

The standard enthalpy or the decomposition of N_2 O_5 to NO_2 is 58.04 kJ and standard entropy of this reaction is 176.7 J/K. The standard free energy change for this reaction at 25^@ C is_____________.

The standard enthalpy or the decomposition of N_2 O_5 to NO_2 is 58.04 kJ and standard entropy of this reaction is 176.7 J/K. The standard free energy change for this reaction at 25^@ C is_____________.

A difinite amount of an ideal gas cfhange its state from state-1 to state-2 isothermally at 300K. If the process is carried out reversibly then work done = -1750 KJ and if the process is carried out irreversibly then work doneis equal to -1000kJ. Calculate DeltaS_(total)=(DeltaS_("system")+DeltaS_("surrounding")) in joule per kelvin for the irreversible isothermal process.

If the first half of the English alphabet is reversed and then next portion of English alphabet is reversed so as ‘A’ takes the position of 'M’ and ‘N’ takes the position of 'Z' then answer the given question. A B C D E F G H I J K L M N O P Q R S T U V W X Y Z Which letter will be 6th to the left of 17th letter to the right of 7th letter from the left? 1) U 2) V 3) C 4) D 5) None of these